Sin^2(X)+2sin(X)+1=0

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Solution for Sin^2(X)+2sin(X)+1=0 equation: 


Simplifying
Sin2(X) + 2sin(X) + 1 = 0

Multiply in2S * X
in2SX + 2sin(X) + 1 = 0

Multiply ins * X
in2SX + 2insX + 1 = 0

Reorder the terms:
1 + 2insX + in2SX = 0

Solving
1 + 2insX + in2SX = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 2insX + -1 + in2SX = 0 + -1

Reorder the terms:
1 + -1 + 2insX + in2SX = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2insX + in2SX = 0 + -1
2insX + in2SX = 0 + -1

Combine like terms: 0 + -1 = -1
2insX + in2SX = -1

Reorder the terms:
1 + 2insX + in2SX = -1 + 1

Combine like terms: -1 + 1 = 0
1 + 2insX + in2SX = 0

The solution to this equation could not be determined.

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